1E2E3E4E5E6E7E8E9E10E11E12E13E14E15E16E17E18E19E20E21E22E23E24E25E26E27E28E29E30E31E32E33E34E35E36E37E38E39E40E41E42E43E44E45E46E47E48E49E50E51E52E53E54RE55RE56RE57RE58RE

Show that Cov(XY) = E

− EE. Hint: By definition, Cov(X, Y) = E<(X − μX)(Y − μY)>. Expand this product, and also use the rules for expectation (Theorem 3.3.1). Remember that μX = E and μY = E.

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Theorem 3.3.1 (Rules for expectation). Let X and Y be random variables and also let c be any type of real number.

**1.** E = c (The intended worth of any type of consistent is that consistent.)

**2.** E = cE (Constants deserve to be factored from expectations.)**3.** E = E + E (The intended worth of a sum is equal to the sum of the meant values.)

Sexactly how that .

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From the interpretation 5.2.2, the formula for the covariance is,

.

Hence,

Introduction to Probcapability and Statistics: Principles and also Applications for Engineering and also the Computing Sciences | fourth Edition

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This is an different ISBN. View the main ISBN for: Summary to Probability and Statistics 4th Edition Textbook Solutions

Review to Probability and also Statistics: Principles and Applications for Engineering and the Computing Sciences (4th Edition) Edit editionSolutions for Chapter 5Problem 24E: Sexactly how that Cov(XY) = E − EE. Hint: By meaning, Cov(X, Y) = E<(X − μX)(Y − μY)>. Expand this product, and use the rules for expectation (Theorem 3.3.1). Remember that μX = E and also μY = E.Theorem 3.3.1 (Rules for expectation). Let X and Y be random variables and also let c be any kind of actual number.1. E = c (The intended worth of any continuous is that consistent.)2. E = cE (Constants have the right to be factored from expectations.)3. E = E + E (The supposed worth of a sum is equal to the amount of the supposed worths.)…